A Car Tire Is Filled With Air At Pressure 325000 Pa At 303 K. When The Tire Cools,its Pressure Reduces (2023)

Answer:

In case of sphere rolls down a smooth inclined plane , work is done by gravity only as in free fall but as it is inclined

So, there comes a factor sin( angle of inclination)

So acceleration becomes g sin( angle of inclination)

Now , As in free fall acceleration is g

And max value of Sin is 1

So ,range of acceleration in smooth inclined plane varies from 0 to g

that is max acceleration or max work done as Work = m × acceleration × displacement

= mg sin ( angle) × displacement

As sin( angle) = height/displacement

So it becomes mg× height

In free fall, Work done = mg × height

So, Free fall work done is same as work done in smooth inclined plane

So, Work done in free fall = work done in smooth inclined plane

Answer:

0.02325 m^3

Explanation:

P1 = 100000Pa , v1 = 0.0279m^3

P2= 120000Pa . V2 = ?

as mass and temperature are constant using ratio method for Boyle'slaw

P2V2= P1V1

or V2= P1V1/P2

V2 = 100000×0.0279/120000

V2= 0.02325 m^3

Answer:

346819 Pa or ,347000 Pa in 3 significant figures

Explanation:

P1= 325000Pa , T1= 283K ,

P2=? T1= 302 K

as here volume and mass both are constant so using ratio method for pressure temperature law we have P1/T1 = P2/T2

THIS WE CAN ALSO OBTAIN BY RATIO METHOD FOR GENERAL GAS LAW AS

P1V1/(m1T1 ) = P2 V2/ (m2 T2)

IF V1 = V2 =V AND m1=m2=m then expression reduces to

P1/T1 = P2/T2

or P2 = (P1/T1)×T2

P2 = (325000/283) × 302

P2 = 1148.41×302

P2=346819

P2 = 347000 Pa in 3 significant figures

Answer:

347000

Explanation:

I just took an exam with this question on it and found this to be the correct answer. For how to solve it look at the above answer.

Answer:

Volume of the container = 0.0618 m³

Explanation:

Assuming that the gas is ideal, we can apply ideal gas equation:

PV=nRT

where P = pressure of the gas

V = volume occupied by the gas

n = number of moles of gas

R = Universal gas constant = 8.314 J/mol-K

T = Temperature of the gas

Here we have to find volume.

Given: P=2.25 atm T=385 K n=4.39 moles

Putting the above values in the ideal gas equation, we get:

Volume of the gas = volume of the container in which it is filled = 0.0618 m³

Answer:

0.0619 m^3

Explanation

number of moles = n = 4.39 mol

pressure = P = 2.25 atm =2.25×1.01×10^5 Pa= 2.27×10^5 Pa

Molar gas constant =R = 8.31 J/(mol K)

Temperature T= 385K

volume of gas = V =?

BY GENERAL GAS LAW WE HAVE

PV = nRT

or V = nRT/P

or V = (4.39×8.31×385)/(2.27×10^5)

V = 0.0618728

V = 0.0619 m^3

Answer:

1 mole has 6.023× 10^23 particles

So, In 0.622 mole no of particles = 6.023× 0.622× 10^23

=3.74 × 10^23

Answer:3.74

Explanation:

Your question asks what a scientific law is.

Your answer would be B). What scientists expect will always happen under particular circumstances

A scientific law is something that will always happen, it is mostly like a repeat when doing a experiment with certain factors in place. This is also known as a "natural law" because something will naturally happen when it is enacted with the same factors for multiple "trials". This "scientific law" will allow scientist to predict what would happen during other multiple trials that are conducted. Concise data would be received from these trials.

An example of a scientific law is Newton's law of gravitation.

Therefore, your answer would be B.

Answer:

3.04 kg up to 3 significant figures

Explanation:

C12H22O11 = 12(12)+22(1)+11(16)= 342 grams = 342÷1000= 0.342 kg

AS atomic mass of carbon is 12 , hydrogen is 1 and of oxygen is 16

now 1 mole has a mass of 0.342 kg

8.88 moles have mass 0.342×8.88=3.04 kg up to 3 significant figures

Answer:

Explanation:

Explanation:

0.566kg *(1mol/0.197 kg)= 2.87 mol gold

note how the units cancel out, if the units do not cancel out (kg/kg=1) then u did something wrong

Answer:

2.87

Explanation:

Answer:

To Calculate Molecular Mass of O3

you should know Atomic mass of O

Atomic mass of oxygen(O) = 16

As O3 consist 3 atoms ,

So, Molecular mass of O3 =>3× 16

=> 48 g/mol

=> 0.048 kg/mol

Answer:

170⁰C

Explanation:

α= ΔL/(lo×Δt)

arranging for Δt

Δt =ΔL/(lo×α)

here Δt is change in temperature, ΔL is change in length,lo is original length and is α coefficient of linear expansion and for copper its value is 17×10^-6

Δt =(0.00130)/(0.450×17×10^-6)

Δt=169.9⁰C

Δt= 170⁰C

The difference in length between the two rods is 0.0025m.

What is the coefficient of linear expansion?

It defines the material's property of expanding when temperature is increased.

The change in length related to the coefficient of linear expansion is given by

ΔL = αLΔT

where ΔT is the change in temperature, L is the original length and ΔL is the change in length.

An aluminum rod and a nickel rod are both 5.00 m long at 20.0°C. The temperature of each is raised to 70.0°C

α aluminum = 23*10^-6

α nickel = 13*10-6

ΔT = 70.0-20.0 = 50.0°C

L=5.00 m

Substitute the values, we get the change in length as

For Aluminum rod :

ΔL=23*10^-6*5.00*50.0 = 0.00575 m

For Nickel rod :

ΔL=13*10^-6*5.00*50.0 = 0.00325 m

The difference in length between the two rods will be

0.00575m -0.00325m = 0.0025m

Thus, difference in length between the two rods is 0.0025m.

Learn more about coefficient of linear expansion.

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Answer:

0.0025 m

Explanation:

If you use the equation ΔL = αLΔT, where ΔL equals the change in length, α equals the linear expansion coefficient, L equals the original length of the object, and ΔT equals the change in temperature, we can calculate the difference in length between the two rods.

α of aluminum = 23*10^-6

α of nickel = 13*10-6

ΔT = 50.0 degrees (derived from the 70.0-20.0)

L=5.00

Once you have gathered all of this given/known information, you may substitute it into the equation. The equation is set up to solve for the change in length so we do not need to do any rearranging. We need to solve one at a time first!

Aluminum:

ΔL=23*10^-6*5.00*50.0 = 0.00575

Nickel:

ΔL=13*10^-6*5.00*50.0 = 0.00325

The final step for solving the difference is simply subtracting the two values we just got to find the difference (similar to what we did when solving for the difference in T):

0.00575-0.00325 = 0.0025

And that's it!! Hope this was helpful!!!

Answer:

170 ⁰C

Explanation:

α= ΔL/(LO×ΔT)

HERE α is coefficient of linear expansion which is constant for different materials , its value for copper is 17×10^-6( ⁰C)^-1

ΔL is change in length , Lo is original length , ΔT is change in temperature

re arranging the equation for ΔT we get

ΔT = ΔL/(LO×α)

= (0.00130)/(0.450× 17×10^-6)

= 169.9⁰C

= 170 ⁰C

Answer:

1.53

Explanation:

α=Δl/(l Δt) here α is coefficient of linear expansion Δl is change in length l is original length andΔt is change in temperature

Δl=0.00174m , l=3.50m ,Δt=21-(-11-5)= 21+11.5 =32.5 ⁰C

α = 0.00174 / (3.50×32.5)

= 1.53×10^-5 ( ⁰C)^-1

Answer:

1.53×10^-5 ( ⁰C)^-1

Answer:

60000N

Explanation:

acceleration is change in velocity

a =(v-u)/t where a is acceleration u is initial velocity and v is final velocity

a = (0-60)/5 = -60/5= - 12m/s^2

here minus sign shows that body is decelerating and force is force of friction Now f = ma here f is force of friction m is mass and a is acceleration

f= 5000×- 12= -60000N

MINUS SIGN HERE SHOWS FORCE OF FRICTION

Hence force of friction is 60000N

Answer:

Total force is 3600N

Explanation:

The forces acting on the body are: the force causing upward motion and the downward force due to the weight of the body.

Upward force F=ma

m=300kg, a=2m/s2

F=300*2

=600N

Downward force F=mg

m=300kg, g=10m/s2

F=300*10

=3000N

The total force needed to lift the load is:

3000+600=3600N

Answer:

3543N OR 3540 N IN 3 SIGNIFICANT NUMBERS

Explanation:

Let F be the force which lifts body upward

in downward direction weight of the body acts .

weight = mass ×acceleration due to gravity

weight, W = 300×9.81=2943N

Now net force acting on body is F-W and according to second law of motion

F-W = m a where F is force W is weight m is mass and a is acceleration

F-2943=300×2

F = 600+2943

F = 3543N or 3540 in 3 significant figures

Answer:

0.54454

104.00902 N

Explanation:

m = Mass of wheel = 100 kg

r = Radius = 0.52 m

t = Time taken = 6 seconds

= Final angular velocity

= Initial angular velocity

= Angular acceleration

Mass of inertia is given by

Angular acceleration is given by

Equation of rotational motion

The coefficient of friction is 0.54454

At r = 0.25 m

The force needed to stop the wheel is 104.00902 N

Answer:

d.

Explanation:

= Radius of the circular path

= Time period of motion

= Angular speed of the motion

Angular speed of the motion is given as

The toy is moving in a circle and hence centripetal acceleration acts on it which can be given as

hence the correct choice is

d.

Answer:8F

Explanation:

Given

Gravitation attraction is F between A and B

if and is the mass of A and B respectively then

F is given by

where r=distance between them

if is doubled and is quadrupled then Force can be given by

thus force becomes 8 times of initial value

Answer:

0.5F OR HALF OF PREVIOUS VALUE

Explanation:

F= G Ma Mb/r²

now new force F1 is given as

F1= G ×2Ma × 0.25 Mb /r²

F1 = 2×0.25 ×Ma×Mb/r²

F1 = 0.5×Ma Mb/r²

F1= 0.5 F

Answer:

8 m/s

Explanation:

= mass of the pickup truck = 4000 kg

= Coefficient of static friction between tires and ice road = 0.13

= Radius of curvature = 50 m

The frictional force between tires and ice road provides the necessary centripetal force to move in circle. hence

centripetal force = frictional force

Answer:

V= 6.974 m/s

Explanation:

Component( box) weight acting parallel and down roof 88(sin39.0°)=55.4 N

Force of kinetic friction acting parallel and up roof = 18.0 N

Fnet force acting on tool box acting parallel and down roof

Fnet= 55.4 - 18.0

Fnet=37.4 N

acceleration of tool box down roof

a = 37.4(9.81)/88.0

a= 4.169 m/s²

d = 4.90 m

t = √2d/a

t= √2(4.90)/4.169

t= 1.662 s

V = at

V= 4.169(1.662)

V= 6.974 m/s